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550x^2-56.7x-44.8=0
a = 550; b = -56.7; c = -44.8;
Δ = b2-4ac
Δ = -56.72-4·550·(-44.8)
Δ = 101774.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56.7)-\sqrt{101774.89}}{2*550}=\frac{56.7-\sqrt{101774.89}}{1100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56.7)+\sqrt{101774.89}}{2*550}=\frac{56.7+\sqrt{101774.89}}{1100} $
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